315+(-62y)+3y^2=0

Solution for 315+(-62y)+3y^2=0 equation:

315+(-62y)+3y^2=0

We get rid of parentheses

3y^2-62y+315=0

a = 3; b = -62; c = +315;
Δ = b2-4ac
Δ = -622-4·3·315
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-8}{2*3}=\frac{54}{6}
=9
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+8}{2*3}=\frac{70}{6}
=11+2/3
$